(2x^2-1)(12x-28)=F

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Solution for (2x^2-1)(12x-28)=F equation: 



(2x^2-1)(12x-28)=

We move all terms to the left:

(2x^2-1)(12x-28)-()=0

We add all the numbers together, and all the variables

(2x^2-1)(12x-28)=0

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